wlmarthabu1rn1s wlmarthabu1rn1s
  • 08-05-2017
  • Physics
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How much energy is released for alpha decay of 236u?

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hahahaf
hahahaf hahahaf
  • 08-05-2017


E = mc^2 = 8.152*10^-30 *(3.00 *10^8)^2 = 7.336 *10^-13 J.
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