contestada

A big cruise ship dropped anchor off the Caribbean island of Barbuda. The heavy anchor was released from a height of 54 meters above the water's surface, and it fell at a constant rate. After 35 seconds, the anchor was 9 meters below the water's surface. How fast did the anchor drop? How long did it take the anchor to reach the water's surface?

Respuesta :

akaleti47
54+9= 63 m = distance and time=35 sec hence, speed= 63/35=9/5=1.8 m/s
time taken to reach water surface= distance/speed=54/1.8=30 sec
calculista

Answer:

Part 1) [tex]1.8\frac{m}{s}[/tex]

Part 2) [tex]30\ sec[/tex]

Step-by-step explanation:

Step 1

Find the speed at which the anchor dropped

we know that

The speed is equal to the distance divided by the time

In this problem the distance is equal to

[tex]54+9=63\ m[/tex]

And the time is equal to [tex]35\ sec[/tex]

substitute and find the speed

[tex]\frac{63}{35}= 1.8\frac{m}{s}[/tex]

Step 2

Find the time taken for the anchor to reach the water's surface

Remember that

[tex]speed=\frac{distance}{time}[/tex]

In this part we have

[tex]speed=1.8\frac{m}{s}[/tex]

[tex]distance=54\ m[/tex]

Substitute and solve for the time

[tex]1.8=\frac{54}{time}[/tex]

[tex]time=54/1.8=30\ sec[/tex]