Answer: The required equation of circle is [tex]x^2-14x+y^2+6y+9=0[/tex]
Step-by-step explanation:
Since we have given that
Centre of circle is (7,-3)
Radius = 7 units
In general , coordinates of centre is (h,k)
and radius is represented by r units.
And the equation of circle is given by
[tex](x-h)^2+(y-k)^2=r^2\\\\(x-7)^2+(y+3)^2=7^2\\\\x^2-14x+49+y^2+6y+9=49\\\\x^2-14x+y^2+6y+58=49\\\\x^2-14x+y^2+6y=49-58\\\\x^2-14x+y^2+6y=-9[/tex]
Hence, the required equation of circle is [tex]x^2-14x+y^2+6y+9=0[/tex]
