Answer:
Patel can use the first and last steps.
Step-by-step explanation:
The given equation is :
[tex]8x^{2} +16x+3=0[/tex]
Patel can use the last step.
[tex]8(x^{2} +2x)+3=0[/tex]
Taking 3 to right hand side, we get
[tex]8(x^{2} +2x)=-3[/tex]
He can also use this step.....
[tex]8(x^{2} +2x+1)=-3+8[/tex]
Upon solving we get,
[tex]8x^{2} +16x+8=-3+8[/tex]
=> [tex]8x^{2} +16x=-3+8-8[/tex]
=> [tex]8x^{2} +16x=-3[/tex]
The quadratic equation is mathematically given as
8(x^{2}+2x+1)=-3+8
Quadratic equation is an equation with degree 2
Question Parameter(s):
Patel is solving 8x2 + 16x + 3 = 0.
Generally, the equation for the statement is mathematically given as
8x^{2}+16x+3=0
8(x^{2}+2x)=-3
8(x^{2}+2x+1)=-3+8
8(x^{2}+2x+1)=5
Hence
x2=-0.79-1
x2=-1.79
In conclusion, the quadratic equation
8(x^{2}+2x)=-3
8(x^{2}+2x+1)=-3+8
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