Answer:
1.47 m
Step-by-step explanation:
Given: The bedspread was 2.4 m long and made an angle of 52 degrees with the ground where it was anchored at each side.
To Find: How wide was the shady area?
Solution:
Refer the attached figure.
The bedspread was 2.4 m long i.e.AC = 2.4 m
The bedspread made an angle of 52 degrees with the ground i.e.∠ACB = 52°
Now we are supposed to find the width of shady area .i.e. BC
We will use trigonometric ratio.
In ΔABC
[tex]Cos \theta = \frac{Base}{Hypotenuse}[/tex]
[tex]Cos 52^{\circ} = \frac{BC}{AC}[/tex]
[tex]Cos 52^{\circ} = \frac{BC}{2.4}[/tex]
[tex]0.61566 = \frac{BC}{2.4}[/tex]
[tex]2.4 \times 0.61566 =BC[/tex]
[tex]1.4775 =BC[/tex]
Hence the width of the shady area is 1.47 m
