The function f(x) is to be graphed on a coordinate plane
At what point should an open circle be drawn?
(–1, 0)
(0, 0)
(0, 1)
(1, 0)

-x, x<0
1, x≥0

Please answer with real answer will mark brainliest if correct

Respuesta :

(0, 1)
Hope it helps

Answer:

The point where the open circle can be drawn on the graph of the function f(x) is:

               (0,0)

Step-by-step explanation:

The function f(x) is given by:

           f(x)=  -x  when x < 0

            and    1  when x ≥ 0

The graph of the function f(x) is a line with a negative slope in the region x<0

and is a straight line parallel to the x-axis in the region x ≥ 0.

We know that in a graph of the function f(x) the open circle is drawn at the point where the inequality is strict i.e. that x is close to some value but could not be equal to that value.

Here x < 0

This means that x is close to zero but does not take the value 0.

Also, when  x is close to zero then f(x)= -0=0

Hence, the open circle is at (0,0)

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