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A rectangular dartboard has an area of 648 square centimeters. The triangular part of the dartboard has an area of 162 square centimeters. A dart is randomly thrown at the dartboard.
Assuming the dart lands in the rectangle, what is the probability that it lands inside the triangle?

To the nearest whole percent, the probability is

A rectangular dartboard has an area of 648 square centimeters The triangular part of the dartboard has an area of 162 square centimeters A dart is randomly thro class=

Respuesta :

calculista

   we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.

The size of the sample space is the total number of possible outcomes

The event space is the number of outcomes in the event you are interested in.

so

the probability is equal to

P=size of the event space/size of the sample space

In this problem

size of the sample size=area of the rectangular dartboard=[tex]648\ cm^{2}[/tex]

size of the event space=area of the triangular part=[tex]162\ cm^{2}[/tex]

[tex]P=\frac{162}{648}=0.25[/tex]

Convert to percentage

[tex]P=0.25*100=25\%[/tex]

therefore

the answer is

[tex]25\%[/tex]

 

The probability that the dart would land inside the triangle given that it lands in the rectangle is  25%.

What is the probability?

Probability measures the chances that an event would occur. The chance that an event would occur lies between 0 and 1.

The probability that the dart would land inside the triangle given that it lands in the rectangle = area of the triangle / area the recentangle

162 / 648 = 25%

To learn more about probability, please check: https://brainly.com/question/13234031