Are you referring to this question?
During a dig, an archaeological team starts at an elevation of −5 1/2 feet. At a rate of 2 3/4 feet per hour, the team digs deeper into the surface for 3 1/2 hours. For the next 4 1/2 hours, the team digs at a rate of 1 5/12 feet per hour. Then the team quits for the day.
How many feet did the archaeological team dig after 3 1/2 hours?
What was the team's elevation at the end of the day?
If so, then let us find out the elevation.
The rate of their dig is 2 3/4 ft per hr for 3 1/2 hours, then the total distance dug after 3 1/2 hours should be: 9 5/8 ft
Here’s how we get the total distance:
First, change mixed number into improper fraction and proceed to multiplication
2 3/4--> 11/4 and 3 1/2 becomes 7/2
Multiply.
11/4 x 7/2 = 77/8
Simplify 77/8--> 9 5/8 ft
Let us move on at the rate of 1 5/12 ft per hr for the next 4 1/2 hr,
Following the same procedure as above, the distance would be: 6 9/24 ft
Distance= 1 5/12 x 4 1/2
= 17/12 x 9/2
= 153/24
= 6 9/24 ft
Thus,to sum up everything, they have a total dug of:
9 5/8 + 6 9/24 = 9 15/24 + 6 9/24 = 16 ft
Then, their elevation on that day is -5 1/2 - 16 = -21 1/2 ft
