Respuesta :
What is the equation for the line of symmetry for the graph of the functiony=-4x^2+6x-8?
C.
x=3/4
C.
x=3/4
the axis of symmetry of y=ax²+bx+c is -b/(2a)
given
y=-4x²+6x-8
a=-4
b=6
axis of symmetry is -6/(2*-4)=-6/-8=6/8=3/4
answer is C
given
y=-4x²+6x-8
a=-4
b=6
axis of symmetry is -6/(2*-4)=-6/-8=6/8=3/4
answer is C