The population of a town 4 years ago was 50,000
people. By this year, the city's population had grown to 63,124 people. Assume the population has grown exponentially and will continue to grow this way. What will be the population of the city 4years from now? Give your answer to the nearest whole number

Respuesta :

Answer:

population will be 79806.

Step-by-step explanation:

Population of a town 4 years ago  was 50,000

Population of town had grown exponentially and present population is 63,124.

So the formula of the population growth will be

[tex]A_{n}=A_{o}(r)^{n-1}[/tex]

Where [tex]A_{n}[/tex] = Final population n = number of years.

           [tex]A_{o}[/tex] = Initial population

           r = rate of increase in population per year.

so  63124 = 50,000 [tex](r)^{4-1}[/tex]

[tex]r^{3}=\frac{63124}{50000}= 1.26428 [/tex]

[tex]r=(1.26428)^{\frac{1}{3} }[/tex]

= 1.0813

Now we have to find the population after 4 years from now.

[tex]A_{n}[/tex] =  [tex]63124(1.08)^{4-1}[/tex]

       =  [tex]63124(1.08)^{3}[/tex]

       = 63124 × 1.264

       = 79806

Therefore, after 4 years from now population will be 79806.