Respuesta :
5xy+4=9
5xy=5
xy=1
y=1/x
So this is of the form kx^(-1), this is not linear as the rate of change is not constant...only kx^1 will have a constant rate of change and be linear.
If you graph it you will see that it is exponential....definitely not a straight line :P
5xy=5
xy=1
y=1/x
So this is of the form kx^(-1), this is not linear as the rate of change is not constant...only kx^1 will have a constant rate of change and be linear.
If you graph it you will see that it is exponential....definitely not a straight line :P