Answer: The reduced fraction is [tex]-\dfrac{1}{7jk}.[/tex]
Step-by-step explanation: We are given to reduce the following fraction to lowest terms :
[tex]F=\dfrac{-5jk}{35j^2k^2}.[/tex]
To reduce the fraction to lowest terms, we need to cancel the terms that are common to both numerator and denominator.
So, we have
[tex]F\\\\\\=\dfrac{-5jk}{35j^2k^2}\\\\\\=-\dfrac{5jk}{5\times 7\times j\times j\times k \times k}\\\\\\=-\dfrac{1}{7jk}.[/tex]
Thus, the reduced fraction is [tex]-\dfrac{1}{7jk}.[/tex]
