Respuesta :

[tex]\bf \textit{area of a sector of a circle}\\\\ A=\cfrac{\theta\pi r^2}{360}\qquad \begin{cases} r=4\\ \theta=112 \end{cases}\implies A=\cfrac{112\cdot 16\cdot \pi }{360}\implies \boxed{A=\cfrac{224}{45}\pi} \\\\\\ A\approx 15.64\\\\ -----------------------------\\\\ \textit{area of a circle is }\pi r^2\textit{ so the other side will be} \\\\\\ \pi r^2-\cfrac{224\pi }{45}\implies 16\pi -\cfrac{224\pi }{45}\implies \boxed{\cfrac{496\pi }{45}}\implies A\approx 34.68[/tex]