kittyb9714
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Juan jogs each day from his house to a local park, and then he jogs back along the same route. On his way to the park, he averages 4 miles per hour. On his way home, he averages 6 miles per hour. If the total trip takes mc006-1.jpg hours, which equation can be used to find x, the distance from Juan’s house to the park?

Respuesta :

tonb
The distance traveled equals the speed v multiplied by the time t

[tex]x = vt[/tex]:

Since the speed varies, and we only know the total time, we must rewrite this as:

[tex]t = \frac{x}{v} [/tex]

If we separate this in the two 'directions', it should add up to one and a half:

[tex]\frac{x}{4} + \frac{x}{6} = 1\frac{1}{2}[/tex]

That would lead me to answer b... (see same question from someone else)
raphealnwobi

The distance from Juan’s house to the park is 3.6 miles

Speed

Speed is the ratio of total distance travelled to total time taken. It is given by:

Speed = distance/ time

When going to the park at 4 mph:

4 = x / t₁

t₁ = x/4

When coming back from the park at 6 mph:

6 = x / t₂

t₂ = x/6

The total trip takes 1 and half hours (1.5 hours)

t₁ + t₂ = 1.5

x/4 + x/6 = 1.5

6x + 4x = 36

x = 3.6 miles

The distance from Juan’s house to the park is 3.6 miles

Find out more on Speed at: https://brainly.com/question/4931057

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