We can apply the Pythagorean theorem
DB² = 15² -12² = 225 - 144 = 81
[tex]DB= \sqrt{81} = 9[/tex]
So, AD = 14 - DB = 14 - 9 = 5
Then AC² = CD² + AD² = 12² + 5² = 144 + 25 = 169
[tex]AC= \sqrt{169} = 13[/tex]
So the perimeter = AB + BC + AC = 14 + 15 + 13 = 42
ANSWER is C) 42
[tex]\textbf{Spymore}[/tex]