A rectangle of perimeter 100 units has the dimensions shown. Its area is given by the function A = w(50 - w). What is the GREATEST area such a rectangle can have?

A) 525 square units
B) 600 square units
C) 625 square units
D) 700 square units

Question

09-05-2017
Mathematics

contestada

A rectangle of perimeter 100 units has the dimensions shown. Its area is given by the function A = w(50 - w). What is the GREATEST area such a rectangle can have?

A) 525 square units
B) 600 square units
C) 625 square units
D) 700 square units

Respuesta :

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apologiabiology apologiabiology · Answer 1 · 2017-05-09T04:28:40+02:00

apologiabiology apologiabiology

09-05-2017

V=LW
hmm, it seems that w=w and l=50-w

P=2(L+W)
P=2(50-w+w)
100=2(50)
duh, doesn't help

expand
A=50w-w^2
take derivitive
A'=50-2w
it equals 0 at w=25
derivitive changes from (+) to (-) at w=25
so that is where the max occurs

l=50-25
l=25

greatest area is 25*25=62

C is answer

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mayelanie mayelanie · Answer 2 · 2019-09-13T19:30:03+02:00

mayelanie mayelanie

13-09-2019

Answer:

Step-by-step explanation:

The answer is C.

Answer Link

A rectangle of perimeter 100 units has the dimensions shown. Its area is given by the function A = w(50 - w). What is the GREATEST area such a rectangle can have? A) 525 square units B) 600 square units C) 625 square units D) 700 square units

Respuesta :

Otras preguntas

A rectangle of perimeter 100 units has the dimensions shown. Its area is given by the function A = w(50 - w). What is the GREATEST area such a rectangle can have?

A) 525 square units
B) 600 square units
C) 625 square units
D) 700 square units