Respuesta :
if xy=0 we assume x and y equal 0
so
the zeros are wehre f(x)=0
0=5(2x-5)(5x+4)
set each to zero
5 is not equal 0 so we don't do that
0=2x-5
5=2x
5/2=x
0=5x+4
-4=5x
-4/5=x
zeroes at x=5/2 and -4/5
so
the zeros are wehre f(x)=0
0=5(2x-5)(5x+4)
set each to zero
5 is not equal 0 so we don't do that
0=2x-5
5=2x
5/2=x
0=5x+4
-4=5x
-4/5=x
zeroes at x=5/2 and -4/5
5(2x-5)(5x+4) = 0
2x-5 = 0
2x = 5
x = 5/2 (Answer)
5x+4 = 0
5x = -4
x = -4/5 (Answer)
2x-5 = 0
2x = 5
x = 5/2 (Answer)
5x+4 = 0
5x = -4
x = -4/5 (Answer)