Respuesta :

We're going to solve each of the systems to determine the solution.

System [tex] 1 [/tex]

[tex] x+y \geq 3\\ x+y \leq 3 [/tex]

using a graph tool

the solution is the line [tex] x+y=3 [/tex]

see the attached figure N [tex] 1 [/tex]

System [tex] 2 [/tex]

[tex] x+y \geq -3\\ x+y \leq 3 [/tex]

using a graph tool

the solution is the shaded area

see the attached figure N [tex] 2 [/tex]

System [tex] 3 [/tex]

[tex] x+y > 3\\ x+y < 3 [/tex]

using a graph tool

The system has no solution

see the attached figure N [tex] 3 [/tex]

System [tex] 4 [/tex]

[tex] x+y > -3\\ x+y < 3 [/tex]

using a graph tool

the solution is the shaded area

see the attached figure N [tex] 4 [/tex]

therefore

the answer is

System [tex] 1 [/tex]

[tex] x+y \geq 3\\ x+y \leq 3 [/tex]



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Answer:

The system of inequality that has a solution set that is a line is:

[tex]x+y\geq 3\\\\x+y\leq 3[/tex]

Step-by-step explanation:

We know that if:

[tex]a\leq b[/tex]

and

[tex]a\geq b[/tex]

Then the resulting equation from both the inequalities is:

                               a=b

Hence, from the option (A) we have:

[tex]x+y\geq 3--------(1)[/tex]

and [tex]x+y\leq 3-------------(2)[/tex]

Hence, the equation that is resulting from the above system of inequalities is:

[tex]x+y=3[/tex]

( Since, the inequality (1) is a solid straight line passing through the point (0,3) and (3,0) and the shaded region is away from the origin, above the line.

and from inequality (2) we get a solid straight line passing through the point (0,3) and (3,0) and the shaded region is towards the origin, below the line )

Hence, the common region that satisfy from both the inequality is a line:

              [tex]x+y=3[/tex]

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