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A bag contains five red marbles, two orange marbles, one yellow marble, and two green marbles. Two marbles are drawn from the bag.

What is the approximate probability of choosing an orange marble and a green marble?

0.02222
0.04444
0.08889
0.13333

Respuesta :

the answer is

[tex] \frac{2}{10} \div \frac{2}{9} = .04444[/tex]
the probability of choosing an orange marble is 2/10 because there are 2 orange marbles and 10 marbles in total.

the probability of choosing a green marble is 2/9 because there are 2 green marbles and 9 marbles in total (because you already picked one marble out of the bag thereby decreasing the total number of marbles in all).

when you multiply the probability of these two events you get .04444 which is the probability of both events happening simultaneously.

The probability of choosing an orange marble and a green marble is 0.0444

What is probability?

"Probability is a branch of mathematics which deals with finding out the likelihood of the occurrence of an event."

Formula of the probability of an event A is:

P(A) = n(A)/n(S)

where,  n(A) is the number of favorable outcomes, n(S) is the total number of events in the sample space.

For given question,

A bag contains 5 red marbles, 2 orange marbles, 1 yellow marble, and 2 green marbles.

Total marbles = 5 + 2 + 1 + 2

Total marbles = 10

The probability of choosing an orange marble is,

⇒ P(A) = [tex]\frac{2}{10}[/tex]

⇒ P(A) = [tex]\frac{1}{5}[/tex]

After selecting one orange marble, there would be 9 marbles in the bag.

The probability of choosing a green marble would be,

⇒ P(B) = [tex]\frac{2}{9}[/tex]

so, the probability of choosing an orange marble and a green marble would be,

⇒ P = P(A) × P(B)

⇒ P = [tex]\frac{1}{5}\times \frac{2}{9}[/tex]

⇒ P = 0.0444

Therefore, the probability of choosing an orange marble and a green marble is 0.0444

Learn more about probability here:

brainly.com/question/11234923

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