Respuesta :
a - 3b = 9
a = 9 + 3b
therefore eq. 1 equals eq.2 (a = b -3)
b - 3 = 9 + 3b
b - 3b = 9 + 3
-2b = 12
b = -6 (Answer)
by substituting b in eq. 2
a = b - 3
a = -6 - 3
a = - 9 (Answer)
(a,b)
(-9,-6)
a = 9 + 3b
therefore eq. 1 equals eq.2 (a = b -3)
b - 3 = 9 + 3b
b - 3b = 9 + 3
-2b = 12
b = -6 (Answer)
by substituting b in eq. 2
a = b - 3
a = -6 - 3
a = - 9 (Answer)
(a,b)
(-9,-6)
Answer:
Option (a) is correct.
The solution to the set of equations in the form (a, b) is (-9 , -6)
Step-by-step explanation:
Given :Two equations are
a − 3b = 9
a = b − 3
We have to find the solution to the set of equations in the form (a, b)
Consider the given system of linear equation,
a − 3b = 9 ......(1)
a = b − 3 ...........(2)
(2) can be written as a - b = - 3 .......(3)
We will solve the given system using elimination method and eliminate a ,
Subtract (3) from (1) , we have,
a − 3b -(a - b) = 9 + 3
-3b + b = 12
-2b = 12
b = - 6
Substitute b = - 6 in (2) , we have,
a = b − 3 ⇒ a = -6 - 3 = -9
Thus, the solution to the set of equations in the form (a, b) is (-9 , -6)
