Respuesta :
In the above reaction the Nitrate ions(NO3^-) and Potassium ion(K^+) are not actively involved in the reaction,hence they are spectactor ions.The only actively involved ions in the solution are the silver ions(Ag+) and the Choride ions(Cl^-) ,they react to form a white precipitate of Silver chloride as follows:
Ag+(aq)+Cl-(aq)=>AgCl(s)
.In the above scenario ,the required answer is only NO3^-(aq)
Ag+(aq)+Cl-(aq)=>AgCl(s)
.In the above scenario ,the required answer is only NO3^-(aq)
B) NO³⁻ (aq) is a spectator ion
Further explanation
The electrolyte in the solution produces ions.
The equation of a chemical reaction can be expressed in the equation of the ions
For strong electrolytes (the ionization rate = 1) is written in the form of separate ions, while the weak electrolyte (degree of ionization <1) is still written as an un-ionized molecule
In the ion equation, there is a spectator ion that is the ion which does not react because it is present before and after the reaction
When these ions are removed, the ionic equation is called the net ionic equation
For gases and solids including water (H₂O) can be written as an ionized molecule
So only the dissolved compound is ionized ((expressed in symbol aq)
Formation of precipitating compounds that cause reactions can occur from double-replacement reactions
Solubility Rules:
soluble compound
All compounds of Li⁺, Na⁺, K⁺, Rb⁺, Cs⁺, and NH₄⁺
All compounds of NO₃⁻ and C₂H₃O₂⁻
Compounds of Cl⁻, Br⁻, I⁻ except Ag⁺, Hg₂²⁺, Pb²⁺
Compounds of SO₄²⁻ except Hg₂²⁺, Pb²⁺, Sr²⁺, Ba²⁺
The reaction between AgNO₃(aq) and KCl(aq)
AgNO₃(aq) + KCl(aq)⇒AgCl(s) + KNO₃(aq)
Complete ion reaction:
[tex]\rm Ag^++NO_3^-+K^++Cl^-\Rightarrow AgCl(s)+K^++NO_3^-\\\\spectator\:ions:K^+\:and\:NO_3^-\\\\net\:ionic\:equation:Ag^++Cl^-\Rightarrow AgCl(s)[/tex]
Learn more
the net ionic equation
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