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The shoe is in contact with the initially nearly stationary 0.500 kg football for 20.0 ms. What average force is exerted on the football in Newtons to give it a velocity of 22 m/s?

Respuesta :

egenriether
If v=22m/s after0.02s then acceleration was
22/0.02=1100m/s^2
Now, F=ma=(0.5)(1100)=550N

Answer:

F = 550 N

Explanation:

As we know that acceleration of the football is given as

[tex]a = \frac{v_f - v_i}{\Delta t}[/tex]

here we know that

[tex]v_i = 0[/tex]

[tex]v_f = 22 m/s[/tex]

[tex]\Delta t = 20 ms[/tex]

now we have

[tex]a = \frac{22 - 0}{20 \times 10^{-3}}[/tex]

[tex]a = 1100 m/s^2[/tex]

now the force exerted on the ball is given as

[tex]F = ma[/tex]

[tex]F = 0.5 \times 1100[/tex]

[tex]F = 550 N[/tex]

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