Answer:
[tex]\frac{b^{7}}{b^{6}}=b[/tex]
Step-by-step explanation:
Hello, I think I can help you with this.
Let's remember some properties of potentiation
[tex]a^{0}=1\\a^{1}=a\\( \frac{a}{b})^{2}=\frac{a^{2}}{b^{2}} \\\\( \frac{a}{b})^{-1}=\frac{b}{a}\\\\\frac{a^{n}}{a^{m}} =a^{n-m}\\[/tex]
Step 1
define
in this case we have a division of two potents with the same base.
according to the last equation
let
[tex]\frac{a^{n}}{a^{m}} =a^{n-m} \\a=b\\n=7\\m=6\\[/tex]
Step 2
replace
[tex]\frac{b^{7}}{b^{6}} =b^{7-6}\\=b^{1}=b\\ hence\\}\\\frac{b^{7}}{b^{6}}=b[/tex]
Have a good day
