Respuesta :
suppose we have had S visitors in n months since EIS (Entry Into Service) of the site, then :
S(n) = 8100 + 8100 * 3 + 8100 * 3^2 + 8100 * 3^3 + ... +8100 * 3^n
S(n) = 8100 * [ 1 + 3 + 3^2 + 3^3 + ... + 3^n ]
and we know that :
1 + 3 + 3^2 + 3^3 + ... + 3^n = (3^(n+1) - 1)/(3 - 1)
= (3^(n+1) - 1)/2
therefore
S(n) = 8100 * (3^(n+1) - 1)/2
finally :
S(n) = 4050 * (3^(n+1) - 1)
and this allows you to obtain the month n, if you know S(n) :
3^(n+1) = S(n) /4050 + 1
therefore :
n = ln[S(n) /4050 + 1] /ln3 - 1
hope it' ll help !!
S(n) = 8100 + 8100 * 3 + 8100 * 3^2 + 8100 * 3^3 + ... +8100 * 3^n
S(n) = 8100 * [ 1 + 3 + 3^2 + 3^3 + ... + 3^n ]
and we know that :
1 + 3 + 3^2 + 3^3 + ... + 3^n = (3^(n+1) - 1)/(3 - 1)
= (3^(n+1) - 1)/2
therefore
S(n) = 8100 * (3^(n+1) - 1)/2
finally :
S(n) = 4050 * (3^(n+1) - 1)
and this allows you to obtain the month n, if you know S(n) :
3^(n+1) = S(n) /4050 + 1
therefore :
n = ln[S(n) /4050 + 1] /ln3 - 1
hope it' ll help !!
The value of the expression for case m = -3 is; N = 300.
What does the value represent?
The value of the expression for m= -3 can be evaluated as follows;
N = 8100 × 3^(-3)
N = 8100 × (1/27
N = 300.
On this note, the value represent the number of visitors 3 months before the number of visitors was measured.
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