Respuesta :
The permutation formula is formulated as:
[tex]\boxed{\text{P(n, r): } \frac{n!}{(n - r)!}}[/tex]
[tex]\text{P(7, 1): } \frac{7!}{(7 - 1)!}[/tex]
[tex]\text{P(7, 1): } \frac{7!}{6!} = 7[/tex]
We can further generalise this for when r = 1.
For when we are taking n objects 1 at a time, we can do this in n ways, because each permutation will be different.
[tex]\boxed{\text{P(n, 1) = } n}[/tex]
[tex]\boxed{\text{P(n, r): } \frac{n!}{(n - r)!}}[/tex]
[tex]\text{P(7, 1): } \frac{7!}{(7 - 1)!}[/tex]
[tex]\text{P(7, 1): } \frac{7!}{6!} = 7[/tex]
We can further generalise this for when r = 1.
For when we are taking n objects 1 at a time, we can do this in n ways, because each permutation will be different.
[tex]\boxed{\text{P(n, 1) = } n}[/tex]
Answer:
The value of P(7, 1) is 7.
Step-by-step explanation:
Given : P( 7, 1)
We have to evaluate the value of P(7, 1)
Consider the given P(7, 1)
[tex]^nP_r[/tex] is defined as the number of the possibility of choosing an ordered set of r objects from a total of n objects.
[tex]nPr=\frac{n!}{\left(n-r\right)!}[/tex]
Put n = 7 and r = 1 , we have,
[tex]=\frac{7!}{\left(7-1\right)!}[/tex]
Simplify, we have,
[tex]=\frac{7!}{\left(7-1\right)!}=7[/tex]
Thus, The value of P(7, 1) is 7.
