A proton is going 2,000 m/s into a magnetic field of 300 T. How much force does it feel. The charge of a proton = 1.602 x 10^-19C

Respuesta :

This depends on the direction of the velocity vector to the magnetic field vector. The force is F=q(VxB)  ("x" is the cross product.)  The max force is when V and B are perpendicular.  Then F=qVB = (1.602e-19)(2000)(300) = 9.612e-14 N