Answer: The percent composition of carbon in carbon monoxide is 43 %.
Explanation:
To calculate the mass percent of an element in a compound, we use the equation:
[tex]\text{Mass percent of element}=\frac{\text{Mass of element in compound}}{\text{Mass of the compound}}\times 100[/tex]
We are given:
Mass of compound = (48 + 64) g = 112 g
Mass of carbon in carbon monoxide = 48 grams
Mass of oxygen in carbon monoxide = 64 grams
Putting values in above equation, we get:
[tex]\text{Mass percent of carbon}=\frac{48g}{112g}\times 100\\\\\text{Mass percent of carbon}=43\%[/tex]
Hence, the percent composition of carbon in carbon monoxide is 43 %.
