If a volume of nitrogen gas at 452 K decreases from 100.0 mL to 50.0 mL, what is the final Kelvin temperature? Assume pressure remains constant.

Respuesta :

100.0mL and 50.0mL to L

452K * (.05L/.10L) = 226 K

Answer : The final temperature of gas will be, 226 K

Explanation :

Charles' Law : It is defined as the volume of gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

[tex]V\propto T[/tex]

or,

[tex]\frac{V_1}{V_2}=\frac{T_1}{T_2}[/tex]

where,

[tex]V_1[/tex] = initial volume of gas = 100 ml

[tex]V_2[/tex] = final volume of gas = 50 ml

[tex]T_1[/tex] = initial temperature of gas = 452 K

[tex]T_2[/tex] = final temperature of gas = ?

Now put all the given values in the above formula, we get the final temperature of the gas.

[tex]\frac{100ml}{50ml}=\frac{452K}{T_2}[/tex]

[tex]T_2=226K[/tex]

Therefore, the final temperature of gas will be, 226 K