Answer:
There is a 6.67% probability that a nickel is drawn first and then a quarter.
Step-by-step explanation:
There are 6 coins. The sum of their values is $0.67. We need to find how many of each coin are there.
A penny is worth 1 cent.
A nickel is worth 5 cents.
A dime is worth 10 cents.
A quarter is worth 25 cents.
To get to 67 cents, we need:
Two pennies, a nickel, a dime and two quarters.
So:
What is the probability that a nickel is drawn first and then a quarter? Assume no replacement and that all coins are equally likely.
Initially there are 6 coins, of which 1 is a nickel. So the probability that the nickel is drawn is:
[tex]P_{1} = \frac{1}{6}[/tex]
There are no replacements, so now there are 5 coins, of which 2 are quarters. So the probability that a quarter is drawn is:
[tex]P_{2} = \frac{2}{5}[/tex].
The probability that a nickel is drawn first and then a quarter is:
[tex]P = P_{1}*P_{2} = \frac{1}{6}{2}{5} = \frac{1}{15} = 0.0667[/tex]
There is a 6.67% probability that a nickel is drawn first and then a quarter.
