Respuesta :
let the distance be x
x +24 1/4 + x = 70 1/3
2x=70-24 +(1/3 - 1/4)=46+(1/12)= 46 1/12
so, x=23 1/24
x +24 1/4 + x = 70 1/3
2x=70-24 +(1/3 - 1/4)=46+(1/12)= 46 1/12
so, x=23 1/24
Answer:
The bar from each edge of the door is [tex]23\frac{1}{24}[/tex] centimeter.
Step-by-step explanation:
Given : You want to place a towel bar that is [tex]24\frac{1}{4}[/tex] centimeters long in the center of a door that is [tex]70\frac{1}{3}[/tex] centimeters wide.
To find : How far should you place the bar from each edge of the door?
Solution :
Let the distance of bar be 'x'.
As we placed the towel bar in the center of the door it divides into two i.e. '2x'
According to question,
[tex]24\frac{1}{4}+2x=70\frac{1}{3}[/tex]
[tex]\frac{97}{4}+2x=\frac{211}{3}[/tex]
[tex]2x=\frac{211}{3}-\frac{97}{4}[/tex]
[tex]2x=\frac{211\times 4-97\times 3}{12}[/tex]
[tex]2x=\frac{844-291}{12}[/tex]
[tex]2x=\frac{553}{12}[/tex]
[tex]x=\frac{553}{12\times 2}[/tex]
[tex]x=\frac{553}{24}[/tex]
[tex]x=23\frac{1}{24}[/tex]
Therefore, The bar from each edge of the door is [tex]23\frac{1}{24}[/tex] centimeter.