Answer:
[tex](x-3)^2+(y-7)^2=36[/tex]
Step-by-step explanation:
We are asked to find the equation of the circle whose center is at (3, 7) and whose radius is 6.
We know that standard equation of circle is in form [tex](x-h)^2+(y-k)^2=r^2[/tex], where,
(h,k) = Center of circle,
r = Radius of circle.
Upon substituting our given values in above formula we will get,
[tex](x-3)^2+(y-7)^2=6^2[/tex]
[tex](x-3)^2+(y-7)^2=36[/tex]
Therefore, the equation of our given circle would be [tex](x-3)^2+(y-7)^2=36[/tex].
