Answer:
Option b is correct
[tex]y=\frac{18}{5}(11)[/tex]
Step-by-step explanation:
The direct variation says that:
[tex]y \propto x[/tex], then the equation is of the form:
[tex]y=kx[/tex] where, k is the constant of variation.
As per the statement:
If y varies directly as x.
By direct variation:
[tex]y = kx[/tex] ....[1]
If y = 18 when x = 5
Substitute these values in [1] we have;
[tex]18 = 5k[/tex]
Divide both sides by 5 we have;
[tex]\frac{18}{5}= k[/tex]
or
[tex]k = \frac{18}{5}[/tex]
⇒[tex]y = \frac{18}{5}x[/tex] ......[2]
We have to find the value of y when x = 11.
Substitute x = 11 in [2] we have;
[tex]y = \frac{18}{5} \cdot 11 = \frac{18}{5}(11)[/tex]
Therefore, the value of y is, [tex]\frac{18}{5}(11)[/tex]
