A small acting club has 6 members. Three of the members are to be chosen for a trip to see a Broadway play. How many different 3 -member groups are possible?

Respuesta :

[tex]6\cdot 5\cdot 4=120[/tex]

or

[tex]C_6^3=3!\cdot {6\choose 3}=3!\cdot \frac{6!}{(6-3)!\cdot 3!}=3\cdot 2\cdot 1\cdot \frac{3!\cdot 4\cdot 5\cdot \not6}{3!\cdot \not3\cdot \not2\cdot 1}=6\cdot 4\cdot 5=120[/tex]