Respuesta :
We have a total of 10 boys & 8 Girls, then the sample space consist of 18 elements.
P(selecting 1 boy) = (total number of boys/by 18) = P(boy)=10/18=5/9
P(selecting 1 boy) = (total number of boys/by 18) = P(boy)=10/18=5/9
Answer:
Probability would be [tex]\frac{5}{16}[/tex] to select both boys.
Step-by-step explanation:
To find the probability of picking two boys, we need to first know how many different ways she can pick the 7th and 8th grader.
There are 10 (5 girls and 5 boys) 7th-graders and 8 (3 girls and 5 boys) 8th-graders. So the total number of ways she can pick is:
10 × 8 = 80
To select two boys, there are 5 boys in the 7th-grade class and 5 in the 8th-grade class, so there are:
5 × 5 = 25 ways
Which gives us the probability of:
[tex]\frac{25}{80}[/tex] = [tex]\frac{5}{16}[/tex]
Probability would be [tex]\frac{5}{16}[/tex] to select both boys.