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The first barn contained 3 times more hay than the second one. After 20 tons of hay were removed from the first barn and 20 tons were added to the second barn, the amount of hay in the second barn was 5/7 of the amount remaining in the first barn. How many tons of hay was there in each barn?

Respuesta :

BlueSky06

The solution would be like this for this specific problem:

 

a + 20 = 5/7 (3a - 20) 
a + 20 = (15a - 100)/7 
Multiply both side by 7, 
7a + 140 = 15a - 100 
8a = 240 
a = 30

3a = 90

a + 20 = 50

3a - 20 = 70

5/7 x 70 = 50

The first barn has 3x - 20 which is 70. And the second barn has x + 20 which is 50.

What is the linear system?

A Linear system is a system in which the degree of the equation is one. It may contain one, two, or more than two variables.

The first barn contained 3 times more hay than the second one.

After 20 tons of hay were removed from the first barn and 20 tons were added to the second barn, the amount of hay in the second barn was 5/7 of the amount remaining in the first barn.

Let x be the amount of the hay.

Then the condition will be

[tex]x \ +\ 20 \ = \dfrac{5}{7} (3x - 20)\\\\7x + 140 = 15x - 100[/tex]

On simplifying, we have the value of x.

15x - 100 = 7x + 140

 15x - 7x = 140 + 100

         8x = 240

           x = 30

Thus, the value of x is 30.

Then the first barn has 3x - 20 which is 70.

And the second barn has x + 20 which is 50.

More about the linear system link is given below.

https://brainly.com/question/20379472

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