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A 42 gram sample of a substance that's used to treat thyroid disorders has a k-value of 0.124. Find the substance's half-life, in days. Round your answer to the nearest tenth.

Respuesta :

wolf1728
k = natural log (.5) / Half-Life
0.124 = .693147 / Half-Life
Half-Life = .693147 / 0.124
Half-Life = 5.5898951613 days
 

Blacklash

Answer:

Half life of sample = 5.59 days

Step-by-step explanation:

We have the equation for half life

           [tex]t_\frac{1}{2}=\frac{ln2}{k}[/tex]

Here decay constant k = 0.124

Substituting

          [tex]t_\frac{1}{2}=\frac{ln2}{0.124}=5.59\boldsymbol{\texttt{ days}}[/tex]

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