Respuesta :
R-2 is age of the second child
R-4 is age of third child
R-2+R-4+R=36
3R= 36+6=42
R=14
R-4 is age of third child
R-2+R-4+R=36
3R= 36+6=42
R=14
The ages of the children are:
R, R-2 and R-4.
Together they are R + R-2 + R-4 = 36. This is an equation we can solve.
3R - 6 = 36 => 3R = 42 => R = 14
So the ages are 10, 12 and 14
R, R-2 and R-4.
Together they are R + R-2 + R-4 = 36. This is an equation we can solve.
3R - 6 = 36 => 3R = 42 => R = 14
So the ages are 10, 12 and 14