The force diagram has four forces: two in the horizontal direction (west - east) and two in the vertical direction (up and down).
The two forces in the horizontal direction are:
1) Force of friction, Ff = 360 N east.
2) Force applied = 1330 N west
=> Net horizontal force = 1330N west - 360N east = 970 west.
Vertical forces:
3) Weight = 990 kg * 9.8 m/s^2 = 9,702 N downward
4) Normal force = - weight = - 9,702N upward
Net vertical force = 9,702N downward - 9,702N upward = 0
5) Second Law of Newton
Net force = m * a => a = Net force / m = 970 N west / 990 kg = 0.98 m/s^2
Then, the conclusion is that the car is moving with uniform acceleration of 0.98 m/s^2 westward (that magnitud is 10% of gravitational acceleration)
