A scientist measured the energy of a system and found that it was increasing. The data shown represent the energy taken every billionth of a second. Time (nanoseconds) 0 1 2 3 Energy (Joules) 2.654 6.290 14.909 35.335 Classify the type of growth the scientist observed.

At start ( t = 0 nanoseconds ) :
E ( t = 0 ) = 2.645 J
E ( t = 1 ) = 6.290 J
E ( t = 1 ) : E ( t = 0 ) = 6.290 : 2.645 = 2.37
Also:
E ( t = 2 ) : E ( t = 1 ) = 14.909 : 6.290 = 2.37
E ( t = 3 ) ; E ( t = 2 ) = 35.335 : 14.909 = 2.37
Therefore, the formula for calculating the energy of the system is:
E ( t ) = 2.645 * 2.37 ^ t
Answer: This is an exponential growth.

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JeanaShupp JeanaShupp · Answer 2 · 2019-03-29T07:45:02+01:00

Answer: exponential growth

Step-by-step explanation:

From the given table, Energy taken by billionth in 1 sec [tex]E_1=2.654[/tex]

Energy taken by billionth in 2 sec [tex]E_2= 6.290 [/tex]

Energy taken by billionth in 3 sec [tex]E_3= 14.909 [/tex]

Energy taken by billionth in 4 sec [tex]E_4= 35.335 [/tex]

Now, [tex]\frac{E_2}{E_1}=\frac{E_3}{E_2}=\frac{E_4}{E_3}=2.37[/tex]

Since, they all have common ratio = 2.37

Hence there is a exponential growth of billionth.

[In exponential growth the ratio of the rate of change of the variable to its current size remains constant over time ]