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The molar mass of copper(II) chloride (CuCl2) is 134.45 g/mol. How many formula units of CuCl2 are present in 17.6 g of CuCl2?
A. 7.88 × 10^22 formula units
B. 1.84 × 10^23 formula units
C. 1.91 × 10^23 formula units
D. 1.42 × 1024 formula units

Respuesta :

Edufirst
You just need to divide the total mass of the compound (CuCl2) by its molar mass (given the the molar mass is the mass of one mole of compound) to find the number of moles. After that, convert the number of moles in number of units.


So,  17.6 g / 134.45 g/mol = 0.1309 moles.


And now use Avogadro's number to convert to number of units:


 => 0.1309 moles * (6.02 * 10^23 units / mol) =0.788*10^ 23 units = 7.88*10^22 units


Answer: option A) 7.88 * 10^ 22 units.
Eduard22sly

The number of formula units present in 17.6 g of CuCl₂ is 7.88×10²² formula units (Option A)

Avogadro's hypothesis

From Avogadro's hypothesis,

1 mole of CuCl₂ = 6.02×10²³ formula units

But,

1 mole of CuCl₂ = 134.45 g

Thus, we can say that:

134.45 g of CuCl₂ = 6.02×10²³ formula units

How to determine the number of formula units

134.45 g of CuCl₂ = 6.02×10²³ formula units

Therefore,

17.6 g of CuCl₂ = (17.6 × 6.02×10²³) / 134.45

17.6 g of CuCl₂ = 7.88×10²² formula units

Thus, 7.88×10²² formula units is present in 17.6 g of CuCl₂

Learn more about Avogadro's number:

https://brainly.com/question/26141731

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