Each of the teams in a mixed volleyball league consists of 5 men and 5 women. There are 9 men and 10 women, including Julia, who are trying out for a team. How many possible teams would include Julia?

5 spots for men and theres 9 men trying out so to find the number of combinations for men the function would be (9*8*7*6*5)/(1*2*3*4*5)=126. the function for women would be (10*9*8*7*6)/(1*2*3*4*5)=252. youd then multiply the two(126*252) and get 31,752.

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facundo3141592 facundo3141592 · Answer 2 · 2022-06-01T16:16:50+02:00

The total number of teams that would include Julia is 15,876.

How many possible teams would include Julia?

For the men's team we need to select 5 out of 9 options, then the total number of different options is:

[tex]C(9, 5) = \frac{9!}{(9 - 5)!*5!} = \frac{9*8*7*6}{4*3*2*1} = 126[/tex]

For the women's case, there are 10, but Julia needs to be on the team, so we only need to select another 4 women from the other remaining 9.

The number of combinations is:

[tex]C(9, 4) = \frac{9!}{(9 - 4)!*4!} = 126[/tex]

The total number of combinations is the product of the two we found:

C = 126*126 = 15,876

We conclude that the correct option is the first one.

If you want to learn more about combinations:

https://brainly.com/question/11732255

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