Respuesta :

mreijepatmat
Let's find the value of the hypotenuse AB = 25+9 = 24 and AB =√34

cos Ф =-5/√34
sin Ф = 3/√34

sec Ф = √34/(-5)

cot Ф = sin Ф/cos Ф = (3/√34)/(-5/√34)

Answer:

given below

Step-by-step explanation:

given point  (−5,3)

using Pythagoras theorem

H² = B² + L²

H² = (-5)² + (3)²

H = √34

now we can see that

Cos θ = [tex]\dfrac{B}{H}[/tex]

Cos θ = [tex]\dfrac{3}{\sqrt{34}}[/tex]

Sec  θ = [tex]\dfrac{H}{B}[/tex]

Sec  θ = [tex]\dfrac{\sqrt{34}}{3}[/tex]

cot θ = [tex]\dfrac{B}{P}[/tex]

cot θ = [tex]-\dfrac{5}{3}[/tex]

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