we know that
m∠SQR+x=[tex]180[/tex] -------> by supplementary angles
so
m∠SQR=[tex]180-x[/tex]
The sum of the internal angles of a triangle is equal to [tex]180[/tex] degrees
m∠SQR+m∠QSR+m∠SRQ=[tex]180[/tex]
substitute the values in the formula
m∠SQR+[tex]35[/tex]+[tex]58[/tex]=[tex]180[/tex]
m∠SQR=[tex]87[/tex] degrees
Find the value of x
m∠SQR=[tex]180-x[/tex]
x=[tex]180[/tex]-m∠SQR
x=[tex]180-87[/tex]
x=[tex]93[/tex] degrees
therefore
the answer is
the value of x is [tex]93[/tex] degrees
