[tex]\bf \textit{Amount for Exponential change}\\\\
A=P(1\pm r)^t\qquad
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{starting amount}\to &133\\
r=rate\to 1.59\%\to \frac{1.59}{100}\to &0.0159\\
t=\textit{elapsed years}\to &6\\
\end{cases}
\\\\\\
\textit{the population is growing, so is a positive rate, +r}
\\\\\\
A=133(1+0.0159)^6[/tex]
