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find the standard equation of the circle having the given center and radius Center (8,-1) Radius 1/3

Respuesta :

ghanami

 

hello :
an equation of the circle Center at the A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a =  8   and b = -1 (Center (8, -1))... r = 1/3 
an equation of the circle is : (x-8)² +(y+1)² = (1/3)²

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