Probability of drawing red first = [tex] \frac{number of red marble }{total number of marbles} [/tex]
Probability of drawing red first = [tex] \frac{3}{ 3 + 4 + 5} [/tex]
= [tex] \frac{3}{12} [/tex] = [tex] \frac{1}{4} [/tex]
Probability of drawing a white marble second = [tex]\frac{number of white marbles }{total number of marbles left}[/tex]
= [tex] \frac{5}{ 2 + 4 + 5} [/tex]
= [tex] \frac{5}{11} [/tex]
Now, probability of drawing first a red and then, without replacement a white marble = [tex] \frac{1}{4} [/tex] × [tex] \frac{5}{11} [/tex]
= [tex] \frac{5}{44} [/tex]
