so hmm notice the picture below
let us check the volume of the larger prism
then we'll see the volume of the cube
then we'll simply divide the larger prism's volume by the cube's and that'd show how many of the cube's volumes can fit in that amount of volume then
[tex]\bf \textit{volume of the larger prism}\\\\
V_l=2\frac{1}{4}\cdot 1\cdot 1\frac{1}{4}\implies V_l=\cfrac{9}{4}\cdot 1\cdot \cfrac{5}{4}\implies V_l=\cfrac{45}{16}
\\\\\\
\textit{volume of the small cube}\\\\
V_c=\cfrac{1}{4}\cdot \cfrac{1}{4}\cdot \cfrac{1}{4}\implies V_c=\cfrac{1}{64}
\\\\\\
\textit{how many times can }\frac{1}{64}\textit{ fit in }\frac{45}{16}\quad ?
\\\\\\
\cfrac{V_l}{V_c}\implies \cfrac{\frac{45}{16}}{\frac{1}{64}}\implies \cfrac{45}{16}\cdot \cfrac{64}{1}\implies 180[/tex]
now.. part B) hmmm looks a bit circular somewhat
the volume of the larger in terms of the cube.. well, is 180 cubes in it, each 1/64 in volume I gather is just 180 * 1/64 then
now...in terms of a "unit cube", meaning a small cube, with sides of 1 unit long
well, a cube of sides 1, is V = 1*1*1, so is V=1
hmmm in terms ..not sure I find that part very clear, sounds like its asking to see how many unit cubes in the large prism.... in which case you can simply do the same division 45/16 divided by 1
