A committee of 4 people is randomly selected from a group of 5 Republicans and 6 Democrats. What is the probability that the committee will be only Democrats?
We have 5 Republican Candidates and 6 Democratic Candidates
We have a total 11 candidates to choose from
First pick of Democratic Candidates = 6/11 Second pick of Democratic Candidates = 5/10 Third pick of Democratic Candidates = 4/9 Fourth pick of Democratic Candidates = 3/8
The probability of four Democratic candidates in the committee is [tex] \frac{6}{11} [/tex]×[tex] \frac{5}{10} [/tex]×[tex] \frac{4}{9} [/tex]×[tex] \frac{3}{8} [/tex] = [tex] \frac{360}{7920} = \frac{1}{22} [/tex]
