The value of the equivalent resistance will be 3.849 ohms. The concept of resistance in parallel is used in a given problem.
Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. It is denoted by R.
The given data in the problem is;
V is the voltage of the storage battery= 12.0 v
R₁ is the resistance 1 = 6.75 ohm
R₂ is the resistance 2 = 15.3 ohm
R₃ is the resistance 3 = 21.6 ohm
The equivalent resistance is found as;
[tex]\frac{1}{R_{eq}} =\frac{1}{R_1} +\frac{1}{R_2} + \frac{1}{R_3} \\\\ \frac{1}{R_{eq}} =\frac{1}{6.75} +\frac{1}{15.3} + \frac{1}{21.6} \\\\ \frac{1}{R_{eq}} =0.25980 \\\\ R_{eq}=3.849 \ ohm[/tex]
Hence the equivalent resistance will be 3.849 ohms.
To learn more about the resistance refer to the link;
https://brainly.com/question/20708652
