Respuesta :
The object’s resultant angle of motion with the +x-axis after the collision is 47°
From object A:
1) x-momentum is 5.7 × 10^4 kilogram meters/second,
2) y-momentum is 6.2 × 10^4 kilogram meters/second.
Now, we know, tanФ = [tex] \frac{y}{x} [/tex]
⇒tanФ = [tex] \frac{6.2 × 10^4 }{5.7 × 10^4} [/tex]
⇒tanФ = 1.088
⇒ Ф = [tex] tan^{-1} [/tex] 1.088
= 47.4 ≈ 47
From object A:
1) x-momentum is 5.7 × 10^4 kilogram meters/second,
2) y-momentum is 6.2 × 10^4 kilogram meters/second.
Now, we know, tanФ = [tex] \frac{y}{x} [/tex]
⇒tanФ = [tex] \frac{6.2 × 10^4 }{5.7 × 10^4} [/tex]
⇒tanФ = 1.088
⇒ Ф = [tex] tan^{-1} [/tex] 1.088
= 47.4 ≈ 47